Bicycle = 2 wheels

tricycle = 3 wheels

Let x be the number of bicycles and

y be the number of tricycles.

2x + 3y = 29

x + y = 11 => x = 11 - y

2x + 3y = 29

2(11 - y) + 3y = 29

22 - 2y + 3y = 29

y = 29 - 22

y = 7

x + y = 11

x + 7 = 11

x = 11 - 7

x = 4

There are 4 bicycles and 7 tricycles.

Check:

2x + 3y = 29

2(4) + 3(7) = 29

8 + 21 = 29

29 = 29 ✔

tricycle = 3 wheels

Let x be the number of bicycles and

y be the number of tricycles.

2x + 3y = 29

x + y = 11 => x = 11 - y

2x + 3y = 29

2(11 - y) + 3y = 29

22 - 2y + 3y = 29

y = 29 - 22

y = 7

x + y = 11

x + 7 = 11

x = 11 - 7

x = 4

There are 4 bicycles and 7 tricycles.

Check:

2x + 3y = 29

2(4) + 3(7) = 29

8 + 21 = 29

29 = 29 ✔

There are 4 bicycles there.

Step-by-step explanation:

29:

we will think of a number to include the tricycles and the bikes so, we will divide the 29 into "21 and 4"

4 = 8÷2 (Because bicycles had 2 wheels)

7 = 21 ÷ 3 (Because tricycles had 3 wheels)

11 riders = 4+7

Therefore there are 4 bicycles there.

7 tricycles x 3 wheels = 21 wheels

4 bicycles x 2 wheels = 8 wheels

21 + 8 = 29 wheels

7 + 4 = 11 riders( since each vehicle has 1 rider)

4 bicycles

Step-by-step explanation:

It is very hard to explain, but I'll try. These were never included in our lessons, so I might explain in a different way than the formula you were thought to do.

Find the digits that make up 29 that is divisible by 3 and 2

Ex.: 21+8, 21 is divisible by 3 and 8 is divisible by 2

21 ÷ 3 = 7 tricycles (and also 7 riders)

8 ÷ 2 = 4 bicycles (also 4 riders)

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