, 14.05.2020maledabacuetes

# Determine the average atomic mass of helium which has two isotopes having atomic masses 4.0026 amu 3.0160 amu The relative abundance of the two isotopes 99.9999 percent and 0.0001 percent respectively.

substitute values in equation: average atomic mass = (0.9893)*(12.000amu) + (0.0107)*(13.003amu) (convert% to decimals) . ... Calculate the atomic mass of lead. The four lead isotopes have atomic masses and relative abundances of 203.973 ampu (1.4%), 205.974 amu (24.1%), 206.976 am (22.1%) and 207.977

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Explanation:

Silicon-28 atom is the stable isotope of silicon with relative atomic mass 27.9769265. The most abundant (92.23 atom percent) isotope of naturally occurring silicon. A trace element that constitutes about 27.6% of the earth's crust in the form of SILICON DIOXIDE. It does not occur free in nature.

Description: Silicon-28 atom is the stable isotope of silicon with relative atomic mass ...

Synonyms: silicon-28silicon-28 atom(28)SiCHEBI:37975(28)14Si

Dates: Modify 2020-11-07; Create 2007-04-30

average atomic mass = 35.454 amu

Explanation:

Solve for the average atomic mass.

average atomic mass = summation of the product of isotopic mass and relative abundance

average atomic mass = 34.968(0.7553) amu + 36.956(0.2447) amu

average atomic mass = 35.454 amu

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Hydrogen and helium are estimated to make up roughly 74% and 24% of all baryonic matter in the universe respectively.

Explanation:

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Explanation:

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1.4% — 203.937/.5 then 52.4%+207.977 -24.1= 64.7x 206.976-22.1%=23.5^4 soo it’ll be 23.5x2 = 47.5%

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