, 01.02.2020enrica11

# Write all the four digit numbers that can be formed using the digits 3,2 and 5 if only the digit 5 can be repeated twice?

9990

Step-by-step explanation:

the numbers should add up to something divisible by 9 but should also end in either 5 or 0, thus the number is 9990

75,498

Step-by-step explanation:

Because if the 4 and 8 respectively are hundreds and ones it should be like this _ _, 4 _ 8. Then put the remaining numbers. This is the result 7 5, 4 9 8. So, the result of it is like this 75,948.

Can you give me the brilliantest answer? Because I explained it well. Pls.

6349

Step-by-step explanation:

Getting the largest 4-digit number with the following conditions:

a. using the digits 3, 4, 6, and 9 only

b. 3 should be in the hundreds place

c. 9 should be in the ones place

thousands - hundreds - tens - ones

_ - 3 - _ - 9

The digits 3 and 9 have been used. Only 4 and 6 are available as well as the thousands and tens place value. We have to put 6 in the thousands place since it is greater than 4. 4 will be put on the remaining blank which is in tens place.

6 - 3 - 4 - 9

= 6349

45,90

9540

Step-by-step explanation:

Just need to find first any number that is divisible by the two and arrange it by greatest to least

231 232 233 234 241 242 243 244 311 312 313 314 321 322 323 324 331 332 333 334 341 342 343 344 411 412 413 414 421 422 423 424 431 432 433 434 441 442 443 444

TOTAL: 40 NUMBERS

TAS LAGYAN NIYO NALANG NG 1,2,3,4 SA ONES DIGIT.

Step-by-step explanation:

1111

Step-by-step explanation:

it's right

6, 349

Step-by-step explanation:

The digits:

3, 4, 6, and 9

Hundreds and ones digits are 3 and 9, respectively:

Hundreds digit: 3

Ones digits: 9

To write the largest 4-digit number with the given conditions above:

_3_ 9

= 6,349

*All you need to do is to arrange them after placing the hundreds and ones digits from the greatest number and below:

2535, 2355, 3255, 3525, 5235, 5253, 5523, 2553, 3552. Thats all i guess..

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