The sum of three consecutive even numbers is 48. what is the smallest of these numbers?

Answers

Let x be the first integer
x+2 the second integer
x+4 the third and largest integer

x+(x+2)+(x+4)=102
3x+6=102
3x=102-6
3x=96
x=32
x+4=32+4=36
the largest even integer is 36

32+34+36=102
102=102

Step-by-step explanation:

32,34,36,

32+34+36=10234


The sum of three consecutive even numbers is 102​

smallest no. = 38

Step-by-step explanation:

let;

1st no. = x

2nd no. = x+2

3rd no. = x+4

solution:

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 120 - 6

3x = 114

3x/3 = 114/3

x = 38 > 1st no. (smallest no.)

x + 2 = 38 + 2 = 40 ---> 2nd no.

x + 4 = 38 + 4 = 42 ---> 3rd no.

check:

x + x + 2 + x + 4 = 120

38 + 38 + 2 + 38 + 4 = 120

120 = 120

Loves Your Family

Step-by-step explanation:

thats all mabuhay ka

answer:

Stream I can't stop me muna

24, 26 & 28 i guess.

24 + 26 + 28 = 78.

2. the number is 15

4. the number is 6

6. 130.00 pesos

8. 4 points

10. 3 cds

12. 38

14. teacher is 30 , student is 15

16. 20 degrees

18

20

sorry it is too long

303234

Step-by-step explanation:

x + (x + 2) + (x + 2 + 2) = 96 \\  \\ x + x + 2 + x + 2 + 2 = 9 6\\  \\ 3x + 6 = 96 \\  \\ 3x = 96 - 6 \\  \\ 3x = 90 \\  \\  \frac{3x}{3}  =  \frac{90}{3}  \\  \\ x = 30

30

30 + 2 = 32

32

32 + 2 = 34

34

#answerForTrees

#BrainlyBookSmart

102
15 is the answer to your question


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