Let x be the first integer

x+2 the second integer

x+4 the third and largest integer

x+(x+2)+(x+4)=102

3x+6=102

3x=102-6

3x=96

x=32

x+4=32+4=36

the largest even integer is 36

32+34+36=102

102=102

x+2 the second integer

x+4 the third and largest integer

x+(x+2)+(x+4)=102

3x+6=102

3x=102-6

3x=96

x=32

x+4=32+4=36

the largest even integer is 36

32+34+36=102

102=102

smallest no. = 38

Step-by-step explanation:

let;

1st no. = x

2nd no. = x+2

3rd no. = x+4

solution:

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 120 - 6

3x = 114

3x/3 = 114/3

x = 38 > 1st no. (smallest no.)

x + 2 = 38 + 2 = 40 ---> 2nd no.

x + 4 = 38 + 4 = 42 ---> 3rd no.

check:

x + x + 2 + x + 4 = 120

38 + 38 + 2 + 38 + 4 = 120

120 = 120

2. the number is 15

4. the number is 6

6. 130.00 pesos

8. 4 points

10. 3 cds

12. 38

14. teacher is 30 , student is 15

16. 20 degrees

18

20

sorry it is too long

303234

Step-by-step explanation:

3030 + 2 = 32

3232 + 2 = 34

34#answerForTrees

#BrainlyBookSmart

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