# I have two bags of counters. The first bag contains 2 RED counters and 1 BLUE counters. The second bag contains 1 RED counter, 1 BLUE counter and 2 YELLOW counters. I take a counter at random from both bags.1. What is the probability that the two counters will be the same color?2. What is the probability that exactly one of the counters will be red?​ answer as a fraction pls reyquicoy4321

ok I understand this questions 123gra

1. If red counter = 3/7

If blue counter = 2/7

2. 3/7 pataojester10
3/12, i used a tree diagram to work it out  alexespinosa

ok I understand this questions shannel99

1. If red counter = 3/7

If blue counter = 2/7

2. 3/7 alexespinosa

blue mixedyellow to be red alexespinosa

Step-by-step explanation:

1) First bag {r,r,b} Second bag {r,b,y,y}

S={(r,r),(r,b),(r,y),(r,y),(r,r),(r,b),(r,y),(r,y),(b,r),(b,b),(b,y),

(b,y)}

= 12

Total number of counters with the same color,

=(r,r),(r,r),(b,b)

= 3

Pr(2 counters of the same color)

= 3/12 = ¼ = 25%

2) Total number of counters with only one red,

=(r,b),(r,y),(r,y),(r,b),(r,y),(r,y),(b,r)

= 7

Pr(counter with only one red)

= 7/12  ### Other questions on the subject: Math Math, 28.10.2019, ShairaGailSanchez
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