5x+3y+(⅓)z=100
x+y+z=100
Solve for (x, y,z)​

Answers

Any number or variable raised to 0 is always equal to 1 so

x^0 = 1
y^0 = 1
z^0 = 1

1+1+1=3

The answer is 3.

x = 20-(3/5)y-(1/15)z

y = (100/3)-(5/3)x-(1/9)z

z = 300-15x-9y

and

x = 100-y-z

y = 100-x-z

z = 100-x-y

Step-by-step explanation:

Solve for x:

Move the expression to the right:

5x+3y+(1/3)z = 100

5x = 100-3y-(1/3)z

Divide both sides by 5:

x = 20-(3/5)y-(1/15)z

Solve for y:

Move the expression to the right:

5x+3y+(1/3)z = 100

3y = 100-5x-(1/3)z

Divide both sides by 3:

y = (100/3)-(5/3)x-(1/9)z

Solve for z:

Multiply both sides by 3:

(5x+3y+(1/3)z = 100)3

15x+9y+z = 300

Move the variables to the right:

z = 300-15x-9y



Do you know the answer?

Other questions on the subject: Math

Math, 28.10.2019, abbigail333
answer:By NCTM President Linda M. GojakNCTM Summing Up, October 3, 2013One of the most memorable moments I had in teaching mathematics occurred in a fifth-grade class. We began the...Read More
1 more answers
Math, 28.10.2019, elaineeee
06 x 56.85 is 3.411 3.411 to the nearest centavo is 3.4 or 3.40...Read More
1 more answers
Math, 28.10.2019, Axelamat
A.Step-by-step explanation:14x × 2 - 7x = 0Calculate the product28x - 7x = 028x - 7x = 0Collect like terms21x = 021x = 0Divide both sides of the equation by 21So, it should be21x...Read More
2 more answers