There are 4 red, 6 blue and 5 green beads to be placed on a string. How many different arrangements can you make?

Answers

This is a combination problem. there are 13c2=78

answer:

+2

step-by-step explanation:

630,630 ways

Step-by-step explanation:

15!

(4!) (5!) (6!)

=630,630 ways



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