Solution:

Find the probability of tossing two dice and showing at least one 4.

So it is non -mutually exclusive;

Let A be the probability of showing 4 in the first die and B be the probability of showing 4 in the second die.

P(A) = 1/6; P(B) = 1/6; P(A & B) = 1/36 for showing at least a 4 in two dice.

Then, we have,

P(A or B) = 1/6 + 1/6 - 1/36

P(A or B) = 11/36

Therefore, the probability of tossing two dice and showing at least one 4 is 11/36.

Find the probability of tossing two dice and showing at least one 4.

So it is non -mutually exclusive;

Let A be the probability of showing 4 in the first die and B be the probability of showing 4 in the second die.

P(A) = 1/6; P(B) = 1/6; P(A & B) = 1/36 for showing at least a 4 in two dice.

Then, we have,

P(A or B) = 1/6 + 1/6 - 1/36

P(A or B) = 11/36

Therefore, the probability of tossing two dice and showing at least one 4 is 11/36.

answer:

What is the probability of rolling a 4 with two dice?

Two (6-sided) dice roll probability table

Roll a…Probability

21/36 (2.778%)

32/36 (5.556%)

43/36 (8.333%)

54/36 (11.111%)

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