Will Fe(OH)3 precipitate from a solution which is 0.1 M in KOH and 0.2 M in K3Fe(CN)6? The dissociation constant for K3Fe(CN)6 is 10^-44.

Answers

Hello!

How is the volume of a gas affected by a decrease in temperature

Yes, much depends on the type of transformation that this gas will pass, for example, we have three types of transformations occurred in a gas, let's see:  

In an isocoric (isometric or isovolumetric) transformation, it is when a certain mass under pressure maintains its constant volume, in front of this if we increase the temperature increases the pressure and if we lower the temperature, the pressure also decreases.  (Charle's Law)In an isobaric transformation, that is, when a particular mass under pressure maintains its constant pressure, on the other hand, as the temperature increases, the volume increases and if the temperature is lowered, the volume decreases. (Gay-Lussac's Law)In an isothermal transformation, that is, its temperature remains constant, if the volume of gas in the container decreases, then its pressure increases, but if the volume increases, then its pressure decreases. (Boyle-Mariotte's Law)

I hope you have understood, it was a pleasure to help, greetings, Dexteright02! =)

Hello!

40.0 moles of H2 gas are pumped into a 20.0 L cylinder at 30.0 degree Celsius. What is the pressure inside the cylinder ?

We have the following data:

n (number of moles) = 40 moles

V (volume) = 20 L

T (temperature) = 30 ºC (in Kelvin)

TK = TºC + 273.15

TK = 30 + 273.15

TK = 303.15 → T (temperature) = 303.15 K

R (gas constant) = 0.0821 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

P*V = n*R*T

P*20 = 40*0.0821*303.15

20\:P = 995.5446

P = \dfrac{995.5446}{20}

P = 49.77723\to\:\boxed{\boxed{P \approx 49.77\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

The pressure inside the cylinder is approximately 49.77 atm

________________________

\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

kepler

Explanation:

The plum pudding model, also known as blueberry muffin model of the atom by jj thomson who discovered the electrons. he said that no matter where matter came from, it contained particles that were the same and are smaller than the atoms that is matter is formed from. 


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