, 15.05.2020reyquicoy4321

# What fraction of the formula weight of each of the ff compounds represents the equivalent weight in a redox process in which the product formed is as indicated: (a) Ce(SO4)2.2(NH4)2SO4.2H2O (->Ce3+) (b) As2O5 (-> As3+) (c) KIO3 (-> ICl32-) (d) Na2SeO4 (-> SeO32-) (e) VOSO4 (-> VO3-) (f) Mo2O3 (-> H2MoO4

KMnO4:KCl = 1:1

HCl:H2O = 2:1

KMnO4:Cl2 = 2:5

HCl:MnCl2 = 8:1

Explanation:

It's pretty straightforward; the ratio of each substance pair is derived from their coefficients in a balanced chemical equation. Just don't forget to make them into their lowest terms.

Hello!

How many mL of a 12.5% (by volume) solution of ethanol are required to produce 175 mL of 0.664 M acetic acid? (density of pure ethanol = 0.789 g/mL)

We have the following data:

% m1/m (percent by solute mass/solution mass) = 12.5

Molar Mass (MM) of ethanol (C2H5OH) ≈ 46.07 g/mol

M1 (molarity) = 0.664 M (or 0.664 mol/L)

V1 (initial volume) = 175 ml = 0.175 L

n (number of mol) = ?

m1 (solute mass - ethanol) = ?

m (solution mass) = ?

d (density of pure ethanol) = 0.789 g/ml

v (volume of pure ethanol) = ? (in ml)

Solving:

[First Step] Let's find the number of moles or matter number, let's see:

If:

[Second Step]  We apply the data to the Molarity or Molar Concentration formula and find the mass of the solute (m1), let's see:

[Third Step] We apply the data to the formula of percent solute mass per solution mass and let's find the solution mass, let's see:

[Fourth Step] We apply the data to the density formula and let's find the volume of ethanol, let's see:

The volume is approximately 54.3 ml

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Bake it at 350°F (175°C) for 50 minutes, until golden brown. Remove the pie from the oven, let it cool for a hot minute and then remove the tin foil and weights. Put the pie back into the oven for 10 minutes. Bake all pies in a rack fitted to the middle of your oven and at 350°F (175°C), always.

The volume of unmixed sugar and water is less than the volume of mixture of sugar and water

Do you know the answer?

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