Crystal Structure
1. Show that the atomic packing factor for HCP is 0.74.
2. Show that the atomic packing factor for BCC is 0.68.

Answers

The answer to this question is MgCI2

a. 0.5

Explanation:

the formula for the determination of sample size estimation is given below:

n=\frac{1.96^{2}p̂q }{d^{2} }

where:

n = sample size

p̂ = proportion of the population

q = 1-p

d = degree of precision

now if the approximation of  p̂ is unknown, then the value of p̂ that will be used is  p̂ = 0.5 to ensure maximum heterogeneity.

1. 2 AgNO3 +   BaCl2  ⇒ 2 AgCl + Ba(NO3)2

Check:    

                    Reactant side              Product side

Ag                     2(1) = 2                           2(1) = 2        

N                       2(1) = 2                                2

O                       2(3) = 6                               6

Ba                          1                                       1

Cl                            2                                 2(1) = 2  

2. 3 MgCl2 + 2 Na3PO4 ⇒ Mg3(PO4)2 + 6 NaCl

Check:    

                    Reactant side              Product side

Mg                     3(1) = 3                           3        

Cl                       3(2) = 6                         6(1) = 1

Na                      2(3) = 6                         6(1) = 1

P                         2(1) =2                            2

O                         2(4) = 8                             8

3. 2 Fe(OH)3 + 3 H2SO4 ⇒ Fe2(SO4)3 + 6 H2O

Check:    

                    Reactant side              Product side

Fe                    2(1) = 2                           2      

O                      2(3) + 12 = 18              12 + 6(1) = 18

H                      2(3) + 6(2) = 12               6(2) = 12

S                       3(1) = 3                            3

The difference between mixture and compound is that mixture can contain components in any proportion while a compound contains components in fixed proportions.


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